How to Evaluate the Derivative of an Inverse Function
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Top Comments (10)
Nice first one and nice vid who agrees 👍
My second teacher 😭🔥
Just came here to say thanks for helping me throughout school. Glad to see you're still posting!
Thank you sir 🥰
Does anybody know where i can go to get a more basic understanding of this topic (more specifically that formula)??
Print The Test - 100 Questions: https://bit.ly/3Zh7X86 Access The Full Test: https://bit.ly/41WNmI9 Derivatives Test Review - Playlist: https://bit.ly/4rkXTqz Direct Link to Part 1 - Q1 to Q50: https://bit.ly/3LRMfob
Just remember dy/dx = 1/(dx/dy)
Please never stop making videos
(f-)'(y)=1/f'(x) The derivative of the inverse function at y is 1/derivative of the function at x. i.e dx/dy=1/(dy/dx) where f(x) must be evaluated at x and f-(y) must be evaluated at y. These follow from y=f(x) and x=f-(y). Confusion is removed if the domain and range are not confused by using the same variable symbol.
00:55 Just holding here for a moment to see if I understand. So, for example, arctan'x = 1/ sec^2 (arctan x), right?
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Top Comments (10)
Nice first one and nice vid who agrees 👍
My second teacher 😭🔥
Just came here to say thanks for helping me throughout school. Glad to see you're still posting!
Thank you sir 🥰
Does anybody know where i can go to get a more basic understanding of this topic (more specifically that formula)??
Print The Test - 100 Questions: https://bit.ly/3Zh7X86 Access The Full Test: https://bit.ly/41WNmI9 Derivatives Test Review - Playlist: https://bit.ly/4rkXTqz Direct Link to Part 1 - Q1 to Q50: https://bit.ly/3LRMfob
Just remember dy/dx = 1/(dx/dy)
Please never stop making videos
(f-)'(y)=1/f'(x) The derivative of the inverse function at y is 1/derivative of the function at x. i.e dx/dy=1/(dy/dx) where f(x) must be evaluated at x and f-(y) must be evaluated at y. These follow from y=f(x) and x=f-(y). Confusion is removed if the domain and range are not confused by using the same variable symbol.
00:55 Just holding here for a moment to see if I understand. So, for example, arctan'x = 1/ sec^2 (arctan x), right?